A ball is thrown in the air from a platform at time t = 0 seconds. The height, h(t), of the ball can be modeled as a function of time, t, by the equation h(t) = -16t + 40t + 20. Approximately how many seconds after being thrown will the ball hit the ground?2.37 seconds1.25 seconds2.93 seconds0.13 seconds

Answer:Option C is the correct answer.Step-by-step explanation:The height, h(t), of the ball can be modeled as a function of time, t, by the equation h(t) = -16t² + 40t + 20When the ball hits the ground, we have h(t) = 0                   h(t) = -16t² + 40t + 20 = 0                     [tex]t=\frac{-40\pm \sqrt{40^2-4\times (-16)\times 20}}{2\times (-16)}=\frac{-40\pm \sqrt{2880}}{-32}\\\\t=\frac{-40\pm 53.67}{-32}\\\\\texttt{t = 2.93s or t = -0.43s}[/tex]Negative time is not possible, so time = 2.93 seconds.Option C is the correct answer.